Use d=1/2gt2 and solve for the time one spends moving upward in a 0.6-m vertical jump. Then double it for the "hang time"-the time one's feet are off the ground.
To solve for the time spent moving upward in a vertical jump and then double it to find the hang time, we can use the formula for vertical displacement:
d = 1/2 * g * t^2
Given that the vertical displacement (d) is 0.6 meters and the acceleration due to gravity (g) is approximately 9.8 m/s^2, we can substitute these values into the equation:
0.6 = 1/2 * 9.8 * t^2
Now, let's solve for t:
Step 1: Multiply both sides of the equation by 2 to eliminate the fraction:
2 * 0.6 = 2 * (1/2 * 9.8 * t^2)
1.2 = 9.8 * t^2
Step 2: Divide both sides of the equation by 9.8 to isolate t^2:
1.2 / 9.8 = t^2
0.1224 ≈ t^2
Step 3: Take the square root of both sides to find t:
√(0.1224) ≈ √(t^2)
t ≈ √0.1224
t ≈ 0.3498 seconds
Now, to find the hang time, we need to double the time spent moving upward:
Hang time = 2 * t
Hang time = 2 * 0.3498
Hang time ≈ 0.6996 seconds
Therefore, the time spent moving upward in the jump is approximately 0.3498 seconds, while the hang time (time with feet off the ground) is approximately 0.6996 seconds.
To solve for the time one spends moving upward in a 0.6-m vertical jump using the equation d = 1/2gt^2, where d is the distance, g is the acceleration due to gravity, and t is the time, we need to rearrange the equation to solve for t.
Given:
d = 0.6 m
g = 9.8 m/s^2 (approximate acceleration due to gravity)
Substituting the values into the equation, we have:
0.6 = 1/2 * 9.8 * t^2
To solve for t, follow these steps:
Step 1: Multiply both sides of the equation by 2:
2 * 0.6 = 2 * 1/2 * 9.8 * t^2
1.2 = 9.8 * t^2
Step 2: Divide both sides of the equation by 9.8:
1.2/9.8 = (9.8 * t^2)/9.8
0.1224 = t^2
Step 3: Take the square root of both sides of the equation:
√0.1224 = √t^2
0.35 ≈ t
Therefore, the time spent moving upward in a 0.6-m vertical jump is approximately 0.35 seconds.
To find the "hang time," which is the time one's feet are off the ground, we need to double the time spent moving upward. Thus, the "hang time" is approximately 2 * 0.35 = 0.70 seconds.