What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare 100.0 milliliters of a 0.50 M acetic acid solution?
c1v1 = c2v2
2.5*v1 = 0.50*100
Solve for v1.
Mconcentrated*Vconcentrated = Mdilute*Vdilute.
To find the volume of the stock solution needed, we can use the equation
(M1)(V1) = (M2)(V2)
where:
M1 = molarity of the stock solution (2.5 M)
V1 = volume of the stock solution we need to find
M2 = molarity of the desired solution (0.50 M)
V2 = final volume of the desired solution (100.0 mL)
Rearranging the equation, we have:
V1 = (M2)(V2) / M1
Substituting the given values:
V1 = (0.50 M)(100.0 mL) / 2.5 M
V1 = 5.0 mL
Therefore, you would need 5.0 mL of the 2.5 M stock solution of acetic acid to prepare 100.0 mL of a 0.50 M acetic acid solution.