7th grade math
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factor the expression 4xsquared+35x+24 my answer: (4x+3)(x8) 4x2 +35x+24= 24 = 2x12 24 = 4x6 24 = 8x3***** (4x+3)(X+8) 4X2 + 3X + 32X +24 + 4XSQ. + 35X + 24
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f(x) = 5x^2  35x I converted ^ that equation to.. 5x^235x = 0 How do I go about from here to determine the zeros and the y intercept?
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Andrew factored the expression 28x^342x^2+35x as 7x(4x^2+6x5). But when Melissa applied the distributive law and multiplied out 7x(4x^2+6x5) , she got 28x^3+42x^235x ; thus, Andrew’s solution does not appear to check. Why is
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Andrew factored the expression 28x^342x^2+35x as 7x(4x^2+6x5). But when Melissa applied the distributive law and multiplied out 7x(4x^2+6x5) , she got 28x^3+42x^235x ; thus, Andrew’s solution does not appear to check. Why is
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