Element Symbol Atomic Mass
---------------------------------------
Bromine Br 79.904
Calcium Ca 40.078
Carbon C 12.011
Chlorine Cl 35.4527
Cobalt Co 58.93320
Copper Cu 63.546
Flourine F 18.9984032
Hydrogen H 1.00794
Iodine I 126.904
Iron Fe 55.847
Lead Pb 207.2
Magnesium Mg 24.3050
Mercury Hg 200.59
Nitrogen N 14.00674
Oxygen O 15.9994
Potassium K 39.0983
Sodium Na 22.989768
Sulfur S 32.066
Please try to show all work for questions 29-33.
29. What mass in grams of sodium hydroxide is produced if 20.0 g of sodium metal reacts with excess water according to the chemical equation 2Na(s)+2H20(l)=2NaOH(aq)+Hs(g)?
30. What mass in grams of 1-chloropropane (C3H7Cl) is produced if 400. g of propane react with excess chlorine gas according to the equation C3H8+Cl2=C3H7Cl+HCl?
31. How many grams of ammonium sulfate can be produced if 30.0 mol of H2SO4 react with excess chlorine gas according to the equation 2NH3(aq)+H2SO4(aq)=(NH4)2SO4(aq)?
32. How many moles of Ag can be produced if 350. g of Cu are reacted with excess AgNO3 according to the equation Cu(s)+2AgNO3(aq)=2Ag(s) +Cu(NO3)2(aq)?
33. What mass in grams of hydrogen gas is produced if 20.0 mol of Zn are added to excess hydrochloric acid according to the equation Zn(s)+2HCl(aq)=ZnCl2(aq)+H2( )?
you should really show what you did (make an attempt), people will not do all of your homework for you here.
It is best for you to post one question per post. ALSO, it is best for you to show what you CAN do and tell us what you CAN'T do (especially what you don't understand how to do). After you have done this someone will be glad to help you finish.
To solve these questions, we need to use the given balanced chemical equations and apply stoichiometry principles. Stoichiometry refers to the relationship between the amounts of substances involved in a chemical reaction.
In each question, we will follow these steps to find the answer:
Step 1: Write the balanced chemical equation for the reaction given.
Step 2: Determine the molar ratio of the substances involved in the equation.
Step 3: Convert the given values (mass or moles) to the desired unit using the molar ratio.
Let's solve the questions one by one:
29. What mass in grams of sodium hydroxide is produced if 20.0 g of sodium metal reacts with excess water according to the chemical equation 2Na(s) + 2H2O(l) = 2NaOH(aq) + H2(g)?
Step 1: Balanced equation: 2Na(s) + 2H2O(l) = 2NaOH(aq) + H2(g)
Step 2: The molar ratio between Na and NaOH is 2:2 (from the balanced equation).
Step 3: Calculate the moles of Na: 20.0 g Na * (1 mol Na / 22.989768 g Na) = 0.8697 mol Na
Using the molar ratio, the moles of NaOH produced are also 0.8697 mol.
Now convert moles to grams: 0.8697 mol NaOH * (39.998 g NaOH / 1 mol NaOH) = 34.79 g NaOH
Therefore, 34.79 grams of sodium hydroxide are produced.
30. What mass in grams of 1-chloropropane (C3H7Cl) is produced if 400. g of propane react with excess chlorine gas according to the equation C3H8 + Cl2 = C3H7Cl + HCl?
Step 1: Balanced equation: C3H8 + Cl2 = C3H7Cl + HCl
Step 2: The molar ratio between propane (C3H8) and 1-chloropropane (C3H7Cl) is 1:1 (from the balanced equation).
Step 3: Calculate the moles of propane: 400. g propane * (1 mol propane / 44.09 g propane) = 9.07 mol propane
Using the molar ratio, the moles of 1-chloropropane produced are also 9.07 mol.
Now convert moles to grams: 9.07 mol C3H7Cl * (58.5 g C3H7Cl / 1 mol C3H7Cl) = 531.495 g C3H7Cl
Therefore, 531.495 grams of 1-chloropropane are produced.
31. How many grams of ammonium sulfate can be produced if 30.0 mol of H2SO4 react with excess ammonia according to the equation 2NH3(aq) + H2SO4(aq) = (NH4)2SO4(aq)?
Step 1: Balanced equation: 2NH3(aq) + H2SO4(aq) = (NH4)2SO4(aq)
Step 2: The molar ratio between H2SO4 and (NH4)2SO4 is 1:1 (from the balanced equation).
Step 3: Calculate the moles of H2SO4: 30.0 mol H2SO4
Using the molar ratio, the moles of (NH4)2SO4 produced are also 30.0 mol.
Now convert moles to grams: 30.0 mol (NH4)2SO4 * (132.14 g (NH4)2SO4 / 1 mol (NH4)2SO4) = 3964.2 g (NH4)2SO4
Therefore, 3964.2 grams of ammonium sulfate can be produced.
32. How many moles of silver (Ag) can be produced if 350. g of copper (Cu) is reacted with excess silver nitrate (AgNO3) according to the equation Cu(s) + 2AgNO3(aq) = 2Ag(s) + Cu(NO3)2(aq)?
Step 1: Balanced equation: Cu(s) + 2AgNO3(aq) = 2Ag(s) + Cu(NO3)2(aq)
Step 2: The molar ratio between Cu and Ag is 1:2 (from the balanced equation).
Step 3: Calculate the moles of Cu: 350. g Cu * (1 mol Cu / 63.546 g Cu) = 5.5156 mol Cu
Using the molar ratio, the moles of Ag produced are 2 times the moles of Cu.
So, the moles of Ag = 5.5156 mol Cu * 2 = 11.0312 mol Ag
Therefore, 11.0312 moles of silver can be produced.
33. What mass in grams of hydrogen gas is produced if 20.0 mol of zinc (Zn) are added to excess hydrochloric acid according to the equation Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(g)?
Step 1: Balanced equation: Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(g)
Step 2: The molar ratio between Zn and H2 is 1:1 (from the balanced equation).
Step 3: Calculate the moles of Zn: 20.0 mol Zn
Using the molar ratio, the moles of H2 produced are also 20.0 mol.
Now convert moles to grams: 20.0 mol H2 * (2.0158 g H2 / 1 mol H2) = 40.316 g H2
Therefore, 40.316 grams of hydrogen gas are produced.