a baseball was launched from 1.5 m above the ground. the ball was caught at a position 4.5m above the ground with a speed of 28m/s moving at a angle of 30 degrees below horizontal:

find initial velocity
- time of flight
- range

To find the initial velocity, time of flight, and range of the baseball, we can break down the problem into its horizontal and vertical components.

First, let's find the initial velocity. We know the speed of the baseball is 28 m/s and the angle below horizontal is 30 degrees. The initial velocity can be found using the horizontal component of the velocity:

Horizontal component of velocity = initial velocity * cos(angle)
Horizontal component of velocity = initial velocity * cos(30°)

Solving for the initial velocity:
initial velocity * cos(30°) = horizontal component of velocity
initial velocity = horizontal component of velocity / cos(30°)

We know that the horizontal component is the speed of the baseball, so:

initial velocity = 28 m/s / cos(30°)

Next, let's find the time of flight. We can use the vertical component of the velocity to find the time it takes for the baseball to reach its maximum height, then double that time to get the total time of flight.

Vertical component of velocity = initial velocity * sin(angle)
Vertical component of velocity = initial velocity * sin(30°)

To calculate the time it takes for the ball to reach its maximum height, we can use the following equation of motion:

final velocity = initial velocity + (acceleration * time)

Where the final velocity at the maximum height is 0 m/s and the acceleration is -9.8 m/s² (acceleration due to gravity). Since the initial velocity at the maximum height is the vertical component, the equation becomes:

0 = Vertical component of velocity - (9.8 m/s² * time to reach maximum height)

Solving for time to reach maximum height:
time to reach maximum height = Vertical component of velocity / (9.8 m/s²)

Since the time to reach maximum height is the same as the time it takes for the ball to descend to the final position, its equation of motion is:

distance = initial velocity * time + (0.5 * acceleration * time²)

We can rearrange this equation to solve for time:

time = (final distance - initial distance) / (initial velocity * sin(angle))

Plugging in the values:
final distance = 4.5 m
initial distance = 1.5 m
initial velocity = initial velocity
angle = 30°

Finally, let's find the range. The range is the horizontal distance traveled by the baseball. We can use the following equation:

range = horizontal component of velocity * time of flight

Plugging in the values:
range = horizontal component of velocity * time of flight

Now that we have all the formulas and steps, we can calculate the initial velocity, time of flight, and range.