How many milliliters of a 0.62 M HCl solution are needed to react completely with 4.7 g of zinc to form zinc(II) chloride?

Answer in units of mL

Write and balance the equation.

Zn + 2HCl ==> ZnCl2 + H2

mols Zn = grams/molar mass
Use the coefficients in the balanced equation to convert mols Zn to mols HCl.
Now M HCl = mols HCl/L HCl. Youhave mols HCl and M HCl, solve for L HCl and convert to mL.

To find the number of milliliters (mL) of a 0.62 M HCl solution needed to react completely with 4.7 g of zinc, we can use the stoichiometry of the reaction balanced equation.

The balanced chemical equation for the reaction between HCl and zinc is:
Zn + 2HCl → ZnCl₂ + H₂

From the balanced equation, we can see that 2 moles of HCl are required to react with 1 mole of zinc.

First, we need to determine the number of moles of zinc present in 4.7 g. To do that, we use the molar mass of zinc, which is 65.38 g/mol.

Number of moles of zinc = Mass of zinc / Molar mass of zinc
Number of moles of zinc = 4.7 g / 65.38 g/mol

Next, we determine the number of moles of HCl required to react with the given amount of zinc by using the stoichiometry ratio from the balanced equation.

Number of moles of HCl = 2 * number of moles of zinc

Finally, we can calculate the volume of the HCl solution in milliliters (mL) using the molarity (M) of the HCl solution.

Volume (mL) = (Number of moles of HCl * Molarity of HCl) / Concentration of HCl

Let's plug in the values to find the solution:
Number of moles of zinc = 4.7 g / 65.38 g/mol
Number of moles of HCl = 2 * (Number of moles of zinc)
Volume (mL) = (Number of moles of HCl * Molarity of HCl) / Concentration of HCl

Now we can substitute the given molarity of HCl solution. Let's assume it is 0.62 M.

Number of moles of HCl = 2 * (4.7 g / 65.38 g/mol)
Volume (mL) = (Number of moles of HCl * 0.62 M) / 0.62 M

Simplifying the equation, we can see that the concentration of HCl cancels out:

Volume (mL) = 2 * (4.7 g / 65.38 g/mol)

Evaluating this expression will give us the result.