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a jar contains $8.75 in nickels, dimes and quarters. There are two times as many dimes as there are nickels, and 10 more dimes than quarters, how many of each coin are in the jar?

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  1. Let x = number of dimes, then x/2 for nickels and
    x-10 for quarters.

    5x/2 + 10x + 25(x-10) = 875

    Solve for x, then x/2 and x-10.

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  2. fygjf

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