how do you know if one is a factor of another without dividing.

a) 4320 can be divided be divided by 2,5,10 evenly. How?

b)can 4230 be divided by 3 and 9?

c) can 98,022 be divided by 2,3,5,9,10? use divisibility rules.

I need help with these questions please i summed it up a little bit.

(a)

If the number is even, it is divisible by 2.
If the number ends with 0 or 5 (the last digit), it is divisible by 5.
If the number ends with 0, it is divisible by 10.

(b)
If the sum of the digits of a number is divisible by 3, it is divisible by 3. For instance, 4320: 4+3+2+0 = 9, and 9 is divisible by 3.
If the sum of the digits of a number is divisible by 9, it is divisible by 9. For instance, 4320: 4+3+2+0 = 9, and 9 is divisible by 9.

(c) Is 98022 divisible by
i. 2 ? -> Yes, cause it's even.
ii. 3 ? -> 9+8+0+2+2 = 21, and 21 is divisible by 3, so yes.
iii. 5 ? -> No it's not, cause it does not end with 0 or 5.
iv. 9 ? -> 9+8+0+2+2 = 21, and 21 is not divisible by 9, so no.
v. 10 ? -> No it's not, cause it does not end with 0.

Hope this helps~ :)

Thanks so much! it helped alot :D

To determine if one number is a factor of another without dividing, you can use divisibility rules. Here's how you can apply them to the given numbers:

a) To check if 2 is a factor of 4320, you can check if the last digit of 4320 is even (divisible by 2), which it is. Therefore, 2 is a factor of 4320.
To check if 5 is a factor of 4320, you can check if the last digit of 4320 is either 0 or 5, which it is not. Therefore, 5 is not a factor of 4320.
To check if 10 is a factor of 4320, you can check if the number ends with a 0, which it does. Therefore, 10 is a factor of 4320.

b) To check if 3 is a factor of 4230, you can add up the digits of 4230 (4 + 2 + 3 + 0 = 9) and see if the sum is divisible by 3, which it is. Therefore, 3 is a factor of 4230.
To check if 9 is a factor of 4230, you can add up the digits of 4230 (4 + 2 + 3 + 0 = 9) and see if the sum is divisible by 9, which it is not. Therefore, 9 is not a factor of 4230.

c) To check if 2 is a factor of 98,022, you can check if the last digit of 98,022 is even (divisible by 2), which it is. Therefore, 2 is a factor of 98,022.
To check if 3 is a factor of 98,022, you can add up the digits of 98,022 (9 + 8 + 0 + 2 + 2 = 21) and see if the sum is divisible by 3, which it is. Therefore, 3 is a factor of 98,022.
To check if 5 is a factor of 98,022, you can check if the last digit of 98,022 is either 0 or 5, which it is not. Therefore, 5 is not a factor of 98,022.
To check if 9 is a factor of 98,022, you can add up the digits of 98,022 (9 + 8 + 0 + 2 + 2 = 21) and see if the sum is divisible by 9, which it is not. Therefore, 9 is not a factor of 98,022.
To check if 10 is a factor of 98,022, you can check if the number ends with a 0, which it does. Therefore, 10 is a factor of 98,022.

To determine if one number is a factor of another without dividing, you can use the concept of divisibility rules. These rules give you clues about whether a number is divisible by certain factors, based on the digits of the number.

a) To check if 4320 can be divided by 2, 5, and 10 evenly:
- For 2: The rule for divisibility by 2 states that a number is divisible by 2 if its last digit is even (0, 2, 4, 6, or 8). The last digit of 4320 is 0, which is even, so 4320 is divisible by 2.
- For 5 and 10: The rule for divisibility by 5 states that a number is divisible by 5 if its last digit is either 0 or 5. The last digit of 4320 is 0, so it is divisible by 5 and, consequently, divisible by 10.

b) To check if 4230 can be divided by 3 and 9:
- For 3: The rule for divisibility by 3 states that a number is divisible by 3 if the sum of its digits is divisible by 3. Adding the digits of 4230 (4 + 2 + 3 + 0) gives 9, which is divisible by 3. Therefore, 4230 is divisible by 3.
- For 9: The rule for divisibility by 9 states that a number is divisible by 9 if the sum of its digits is divisible by 9. The sum of the digits of 4230 (4 + 2 + 3 + 0) is 9, which is divisible by 9. Therefore, 4230 is also divisible by 9.

c) To check if 98,022 can be divided by 2, 3, 5, 9, and 10:
- For 2: The rule for divisibility by 2 is as mentioned earlier. Since the last digit of 98,022 is 2, which is even, 98,022 is divisible by 2.
- For 3: The rule for divisibility by 3 was mentioned earlier as well. The sum of the digits of 98,022 (9 + 8 + 0 + 2 + 2) is 21. Since 21 is divisible by 3, 98,022 is also divisible by 3.
- For 5 and 10: Both 5 and 10 were discussed earlier. Since the last digit of 98,022 is 2, which is not 0 or 5, it is not divisible by 5 or 10.
- For 9: Again, the rule for divisibility by 9 was explained earlier. The sum of the digits of 98,022 (9 + 8 + 0 + 2 + 2) is 21, which is not divisible by 9. Therefore, 98,022 is not divisible by 9.