When 0.03 moles of aluminum sulfate are dissolved in enough water to make 266 mililiters of solution, what is the molarity of sulfate ions?
Answer in units of M
Al2(SO4)3 = 0.03 mols
M Al2(SO4)3 = 0.03/0.266L = about 0.113
M SO4^2- = 3x that.
To find the molarity of sulfate ions, we need to first determine the number of moles of sulfate ions present in the solution.
Aluminum sulfate (Al2(SO4)3) dissociates in water as follows:
Al2(SO4)3 (s) → 2 Al3+ (aq) + 3 SO42- (aq)
From the balanced equation, we can see that each formula unit of aluminum sulfate produces three moles of sulfate ions (SO42-).
Given that there are 0.03 moles of aluminum sulfate in the solution, we can calculate the moles of sulfate ions as follows:
moles of sulfate ions = 0.03 moles of aluminum sulfate × 3 moles of sulfate ions / 1 mole of aluminum sulfate
moles of sulfate ions = 0.09 moles
Next, we need to determine the volume of the solution in liters. We are given that the volume is 266 milliliters, which is equivalent to 266/1000 = 0.266 liters.
Finally, we can calculate the molarity (M) of sulfate ions using the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
Molarity = 0.09 moles / 0.266 liters = 0.34 M
Therefore, the molarity of sulfate ions in the solution is 0.34 M.
To find the molarity of sulfate ions in the solution, we need to first calculate the number of moles of sulfate ions present.
Aluminum sulfate (Al2(SO4)3) has two sulfate ions (SO4^2-) per formula unit. Therefore, if we have 0.03 moles of aluminum sulfate, we also have 0.03 moles of sulfate ions.
Next, we need to determine the volume of the solution in liters. Given that we have 266 milliliters of solution, we convert this volume to liters by dividing by 1000:
266 mL ÷ 1000 mL/L = 0.266 L
Now that we know the number of moles of sulfate ions (0.03 moles) and the volume of the solution in liters (0.266 L), we can calculate the molarity (M).
Molarity (M) is defined as moles of solute per liter of solution.
Molarity (M) = moles of solute / volume of solution (in liters)
Molarity of sulfate ions = 0.03 moles / 0.266 L
Calculating the molarity:
Molarity of sulfate ions = 0.113 M
Therefore, the molarity of sulfate ions in this solution is 0.113 M.