A 2.00 square meter flat surface is placed in a uniform electric field of magnitude 6.00 N/C. If the surface is oriented so that the field lines are all parallel to the surface, find the magnitude of the electric flux through this area
Parallel to the surface? Isn't flux the E field that goes through the surface? It has to be zero through the surface.
To find the magnitude of the electric flux through the given area, we can use the formula:
Electric Flux = Electric Field * Area * cos(θ)
Where:
Electric Field (E) = 6.00 N/C (given)
Area (A) = 2.00 square meter (given)
θ = angle between the electric field lines and the surface (in this case, 0 degrees since the field lines are all parallel to the surface)
Substituting the given values into the formula, we get:
Electric Flux = (6.00 N/C) * (2.00 square meter) * cos(0 degrees)
Since cos(0 degrees) = 1, the equation simplifies to:
Electric Flux = (6.00 N/C) * (2.00 square meter) * 1
Electric Flux = 12.00 N·m²/C
Therefore, the magnitude of the electric flux through the given area is 12.00 N·m²/C.