express dissipated power in terms of voltage and resistance.
express dissipated power in terms of current and resistance
a boy whose mass is 40kg can run up a flight of 45 steps each 16cm high in 5.2 seconds. find the power develop
P = V^2/R
P = I^2 * R
The dissipated power (P) in an electrical circuit can be expressed in terms of voltage (V) and resistance (R) using Ohm's Law:
P = V^2 / R
This equation shows that the power dissipated in a circuit is proportional to the square of the voltage and inversely proportional to the resistance.
Alternatively, the dissipated power can also be expressed in terms of current (I) and resistance (R) using the equation:
P = I^2 * R
This equation shows that the power dissipated in a circuit is proportional to the square of the current and directly proportional to the resistance.
Dissipated power, denoted as P, can be expressed in terms of voltage (V) and resistance (R) using the formula P = V^2 / R. This equation is derived from Ohm's Law, which states that the voltage across a resistor is equal to the current flowing through it multiplied by its resistance (V = I * R).
To obtain this equation, we start with Ohm's Law: V = I * R. We can rearrange this equation to solve for current (I) as I = V / R. Substituting this value into the formula for power, P = V * I, we get P = V * (V / R).
Simplifying further, P = V^2 / R.
Now, let's express dissipated power in terms of current (I) and resistance (R). From Ohm's Law, we know that V = I * R. Substituting this into the power equation, we have P = (I * R) * I.
Simplifying further, P = I^2 * R.
So, dissipated power can be expressed either as P = V^2 / R in terms of voltage and resistance, or as P = I^2 * R in terms of current and resistance.