for the polynomial function h(x)=2x to the 4th power-x to the 3rd power+2x to the 2nd power -4x-3 evaluate h(3)
h(x) = 2x^4 - x^3 + 2x^2 - 4x - 3
h(3) = 2*3^4 - 3^3 + 2*3^2 - 4*3 - 3
= 2*81 - 27 + 2*9 - 4*3 - 3
= 162-27+18-12-3
= 138
To evaluate the function h(x) = 2x^4 - x^3 + 2x^2 - 4x - 3 at x = 3, you simply substitute x = 3 into the function and compute the result.
Step 1: Replace every occurrence of x in the function h(x) with 3.
h(3) = 2(3)^4 - (3)^3 + 2(3)^2 - 4(3) - 3
Step 2: Simplify using the order of operations (parentheses, exponents, multiplication/division from left to right, addition/subtraction from left to right).
h(3) = 2(81) - 27 + 2(9) - 12 - 3
Step 3: Compute the values inside parentheses and perform any necessary computations.
h(3) = 162 - 27 + 18 - 12 - 3
Step 4: Perform addition and subtraction from left to right.
h(3) = 138 + 18 - 12 - 3
h(3) = 156 - 12 - 3
h(3) = 144 - 3
Step 5: Compute the final result.
h(3) = 141
Therefore, h(3) = 141.