A canal lock gate is 20m wide and 10m deep. calculate the thrust acting on it assume that the water in the canal is in level with the top of the gate. density of water is 1000kg/m^3
Hydrostatic pressure p varies linearly with height h, i.e.
p=ρgh
For a height of H and width of W, total force, F
= W∫ρgh dh
=ρgH²W/2
Ensure that all values are in SI units.
.Suppose an astronaut drops a feather from 1.2 m above the surface of the moon. If the acceleration due to gravity on the moon is m/s^2 downward, how long does it take the feather to hit the Moon's surface?
To calculate the thrust acting on a canal lock gate, you need to consider the pressure exerted by the water on the gate.
1. Calculate the pressure exerted by the water:
Pressure = density of water × acceleration due to gravity × height of water
= 1000 kg/m^3 × 9.8 m/s^2 × 10 m
= 98,000 N/m^2
2. Calculate the area of the gate:
Area = width of the gate × depth of the gate
= 20 m × 10 m
= 200 m^2
3. Calculate the thrust:
Thrust = Pressure × Area
= 98,000 N/m^2 × 200 m^2
= 19,600,000 N
Therefore, the thrust acting on the canal lock gate is 19,600,000 Newtons.
To calculate the thrust acting on a canal lock gate, we need to determine the pressure exerted by the water on the gate. The pressure is given by the equation:
Pressure = Density x gravitational acceleration x height
Where:
- Density is the density of water (1000 kg/m^3)
- Gravitational acceleration is the acceleration due to gravity (9.8 m/s^2)
- Height is the depth of the water (10 m)
First, let's calculate the pressure exerted by the water on the gate:
Pressure = 1000 kg/m^3 x 9.8 m/s^2 x 10 m
Pressure = 98,000 N/m^2
Now, let's calculate the area of the gate:
Area = Width x Depth
Area = 20 m x 10 m
Area = 200 m^2
Finally, we can calculate the thrust acting on the gate by multiplying the pressure by the area:
Thrust = Pressure x Area
Thrust = 98,000 N/m^2 x 200 m^2
Thrust = 19,600,000 N
Therefore, the thrust acting on the canal lock gate is 19,600,000 Newtons.