please help me figure this
select x-coordinate of the vertex of the parabola defined by the function
f(x) = -5x^2 + 9x + 2
for a function y = ax^2 + bx + c
the x-coordinate of the vertex is -b/(2a)
let me know what you got for the x-coordinate
Select the x-coordinate of the vertex of the parabola defined by the function f(x)=-3x^2+7x+8
To find the x-coordinate of the vertex of a parabola, you can use the formula:
x = -b / (2a)
In the given function f(x) = -5x^2 + 9x + 2, the coefficients are a = -5 and b = 9.
Plugging these values into the formula, we get:
x = -9 / (2 * -5)
Simplifying further:
x = -9 / -10
This gives us:
x = 0.9
Therefore, the x-coordinate of the vertex of the parabola defined by the function f(x) = -5x^2 + 9x + 2 is 0.9.