in the diagram AB=20 cm, BC=21 cm, AD=10 cm and DE= 10.5 cm. Angles ABC and ADE are right angles. if triangle ADE is removed from triangle ABC.What is the area of shaded region that remains?

You need to be PATIENT and wait for a math tutor to come online. Currently, I don't see any of them online.

Do not repost. Reposts will be deleted.

the maths tutor where online because ques which were posted after me were answered, and why reposts will be deleted

Since there is no diagram available here, it's hard to see just where D and E are. I can visualize a large right triangle ABC, but I'm not sure where the smaller triangle ADE is located.

here is the diagram Steve but it is not perfect.

All sides are in cm. there r no dotted lines, but i didn't had any choice.
/|
/ |
/ |
/ |
/ |
/ |
/ |
/ 10.5 |
/\ |
10 / \ |
/ \ |
/ \ |
A ------------ B
E
______20______

i did not made the diagram like this.......

the answer is...

idk ;D

To find the area of the shaded region, we need to find the area of triangle ABC and subtract the area of triangle ADE.

To find the area of triangle ABC, we can use the formula for the area of a triangle:

Area = (base * height) / 2

In triangle ABC, AB is the base and BC is the height. So, the area of triangle ABC is:
Area_ABC = (AB * BC) / 2

Substituting the given values, we have:
Area_ABC = (20 cm * 21 cm) / 2 = 210 cm^2

Now, let's find the area of triangle ADE. Again, we can use the same formula:
Area_ADE = (base * height) / 2

In triangle ADE, AD is the base and DE is the height. So, the area of triangle ADE is:
Area_ADE = (AD * DE) / 2

Substituting the given values, we have:
Area_ADE = (10 cm * 10.5 cm) / 2 = 52.5 cm^2

Finally, to find the area of the shaded region, we need to subtract the area of triangle ADE from triangle ABC:
Area_shaded = Area_ABC - Area_ADE
Area_shaded = 210 cm^2 - 52.5 cm^2
Area_shaded = 157.5 cm^2

Therefore, the area of the shaded region that remains after removing triangle ADE from triangle ABC is 157.5 cm^2.