math

how do i factorise
a)9a^2-b^2
b)3x-8y-4xy+6

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  1. the first one is a simple case of "difference of squares"
    (3a+b)(3a-b)

    the second one is the "grouping" type
    3x-8y-4xy+6
    = 3x + 6 - 4xy - 8y
    = 3(x+2) - 4y(x+2)
    = (x+2)(3-4y)

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    posted by Reiny

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