A sheet of aluminum (Al) foil has a total area of 2.119 ft2 and a mass of 2.714 g. What is the thickness of the foil in millimeters? (Density of Al = 2.699 g/cm3?
2.119ft^2 * 2.699g/cm^3 / 2.714g * (30.48cm/ft)^3 =
2.714g * 2.699g/cm^3 * (30.48cm/ft)^3
thickness = volume/area
= mass/density/area
= (2.714g)/(2.699g/cm^3)/(2.119ft^2) * 1ft/30.48cm = 5.108*10^-4 cm
Seems kind of thin. Better double-check my math
To find the thickness of the aluminum foil, we can use the formula:
Thickness = Mass / (Density x Area)
First, let's convert the area from square feet to square centimeters:
1 square foot = 929.03 square centimeters
So, the area of the aluminum foil in square centimeters is:
Area = 2.119 ft^2 * 929.03 cm^2/ft^2 = 1971.18 cm^2
Now we can substitute the values into the formula:
Thickness = 2.714 g / (2.699 g/cm^3 * 1971.18 cm^2)
Calculating this, we find:
Thickness = 0.000689 cm
To convert the thickness to millimeters, we'll multiply by 10:
Thickness = 0.000689 cm * 10 = 0.00689 mm
Therefore, the thickness of the aluminum foil is approximately 0.00689 mm.