A sheet of aluminum (Al) foil has a total area of 2.119 ft2 and a mass of 2.714 g. What is the thickness of the foil in millimeters? (Density of Al = 2.699 g/cm3?

2.119ft^2 * 2.699g/cm^3 / 2.714g * (30.48cm/ft)^3 =

2.714g * 2.699g/cm^3 * (30.48cm/ft)^3

thickness = volume/area
= mass/density/area
= (2.714g)/(2.699g/cm^3)/(2.119ft^2) * 1ft/30.48cm = 5.108*10^-4 cm

Seems kind of thin. Better double-check my math

To find the thickness of the aluminum foil, we can use the formula:

Thickness = Mass / (Density x Area)

First, let's convert the area from square feet to square centimeters:

1 square foot = 929.03 square centimeters

So, the area of the aluminum foil in square centimeters is:

Area = 2.119 ft^2 * 929.03 cm^2/ft^2 = 1971.18 cm^2

Now we can substitute the values into the formula:

Thickness = 2.714 g / (2.699 g/cm^3 * 1971.18 cm^2)

Calculating this, we find:

Thickness = 0.000689 cm

To convert the thickness to millimeters, we'll multiply by 10:

Thickness = 0.000689 cm * 10 = 0.00689 mm

Therefore, the thickness of the aluminum foil is approximately 0.00689 mm.