physics

A boy sledding down a hill accelerates at 1.20 m/s2. If he started from rest, in what distance would he reach a speed of 7.00 m/s?

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asked by james
  1. Use:
    v(t) = v(0) + a t
    With values:
    (7.00m/s) = (0.00m/s) + (1.20m/s^2) t
    Solve for t.

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    posted by Graham
  2. V^2 = Vo^2 + 2a*d
    d = (V^2-Vo^2)/2a
    d = (7^2-0)/2.4

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    posted by Henry

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