AP Calc

Find the equation of the tangent line at the indicated point.

y=5th root of (3x^3+4x) at (2,2)

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asked by Anon
  1. y = (3x^3+4x)^(1/5)
    y' = 1/5 (3x^3+4x)^(-4/5) * (9x^2+4)
    y'(2) = (1/5)(1/16)(40) = 1/2

    So, now you have a point and a slope. Go for it.

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    posted by Steve

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