Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Chemistry
for a reversible reaction if the concentration of reactant are doubled aad a definate tempreture then equilibrium constant will
1 answer
Your post isn't very clearly stated; however, I think you are asking if the Keq will change when the reactant concentrations are doubled. The answer is no. The reaction will shift to the right (more products) but K will not change.
You can
ask a new question
or
answer this question
.
Similar Questions
At a given temperature, for a reversible reaction , if the concentration of reactants is doubled then the equilibrium costant
Top answer:
(d) remaine same
Read more.
the reaction A+3B—>2C+D is first order with respect to reactant A and second order with respect to reactant B if the
Top answer:
rate=constant*a^2 ( b^3) = constant*4* 1/8= 1/2 rate
Read more.
the reaction A+3B->2C+D is first order with respect to reactant A and second order with respect to reactant B if the
Top answer:
see other post.
Read more.
the reaction A+3B->2C+D is first order with respect to reactant A and second order with respect to reactant B if the
Top answer:
To determine how the rate of the reaction would change when the concentration of A is doubled and
Read more.
In a chemical reaction, the forward rate is greater than the reverse rate. Which statement about the reaction is correct?
The
Top answer:
The reaction is reversible is correct! @DrBob222 is also correct
Read more.
In a chemical reaction, the forward rate is greater than the reverse rate. Which statement about the reaction is correct?
The
Top answer:
1. Nitrogen and hydrogen combine at the same rate that ammonia breaks down. 2. Both calcium
Read more.
if the initial concentration of the reactant in the first order reaction A→products is 0.64 mol/L and the half-life is 30 s,
Top answer:
half lives = 120/30 = 4 2^4 = 16 and 0.64/16 = ??
Read more.
calculate the half-life of a first- order reaction if the concentration of the reactant is 0.0396 M at 12 seconds after the
Top answer:
ln(No/N) = kt No = 0.0396 N = 0.00579 k = solve t = 47-12 = 35 seconds. Solve for k, then k =
Read more.
calculate the half-life of a first- order reaction if the concentration of the reactant is 0.0396 M at 12 seconds after the
Top answer:
I worked this for you below.
Read more.
can you fix the grammar
Rate of reaction refers to speed of the concentration of reactant convert to product the formula states
Top answer:
The rate of reaction refers to the speed at which the concentration of a reactant converts to a
Read more.
Related Questions
1. The rate of a chemical reaction may be defined as:
a) The speed at which a molecule travels from point A to point B. b) The
A first-order reaction has a rate constant of 0.547 min - 1. How long will it take a reactant concentration 0.14 M to decrease
If the initial rate of reaction is observed to increase by a factor of nine when the concentration of a reactant is tripled,
Consider the reversible reaction: A(g)-2B(g)At equilibrium, the concentration of A is 0.381 M and that of B is 0.154 M. What is
A decomposition reaction is found to be first order with respect to the reactant. What is the relationship between the rate and
The initial concentration of a reactant in a first order reaction is 0.620 molar. What will be its concentration after 3
It takes 42.0 min for the concentration of a reactant in a first-order reaction to drop from 0.45 M to 0.32 M at 25C. How long
Which of the following changes generally lead to greater reaction rates?
(I)Increasing the temperature (II)Decreasing the
The half-life of a first order reaction is determined to be 65.0 years. How long will it take for the concentration of the
can youi fix the grammar
Rate of reaction refers to the speed at which the concentration of reactant converts to a product, the