Math
 👍 0
 👎 0
 👁 31
Respond to this Question
Similar Questions

Math
k such that 3 is the remainder when f(x)=x to the 4 power minus 4xcube minus 8xsquare minus 7x plus 1. Tapos which of the following binomial factor of 2xcube plus 5xsquared minus 10x plus 16.
asked by Albert on October 1, 2017 
algebra
when x=3 and y=5 how much does the value of 3x to the seond power minus 2y to the second power exceed the value of 2x to the second power minus 3y
asked by tiara on August 11, 2009 
algebra ll
i answersd this question and i got it wrong i don't know why if you can answer it and show the work so ican understand thank you. evaluate h(negative2/3) if h(X)eqauls [[x minus 2. my answers is (negative 2/3)minus 2)
asked by Anonymous on October 6, 2008 
algebra ll
i answersd this question and i got it wrong i don't know why if you can answer it and show the work so ican understand thank you. evaluate h(negative2/3) if h(X)eqauls [[x minus 2. my answers is (negative 2/3)minus 2)
asked by Anonymous on October 7, 2008 
dividing monomials
i don't know what to do when their is a smaller number on top Give an example and tell us what you don't understand. (c)2d7/c2d6 d i just don't get it do u have some examples? What is X squred minus 5X plus 4 divided by X minus 1
asked by joeyg on November 20, 2006 
MATHS
SIMPLIFY SIN RAISE TO POWER 4 MINUS COS RAISE TO POWER4 DIVIDED BY 1 MINUS 2SIN RAISE TO POWER 2
asked by CATHERINE on March 26, 2017 
math
11 the 2 second power minus 7 times 6 minus 4 to the third power divided by 2
asked by Lulu on February 12, 2018 
algebra 1
I have to simplfy by dividing n to the third power minus 8 divided by n minus two
asked by daniel reed on August 16, 2010 
algebra
How would you solve polynomial equation for, a to the 8th power minus a to the 2nd power and b to the 6th power?
asked by Amy on March 17, 2014 
algebra
43/4b^5c^3 / 4/6b^2c^3 = four minus three fourths b to the 5th power c to the third power divided by negative four sixths b to the second power and c to the negative 2 power
asked by Lisa on February 18, 2009