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If alpha and beta are the roots of the equation 2x^2+ 4x + 1 = , find the values of log2alpha + log2beta

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asked by kim jung hee

  1. If 2x²+4x+1 = 0
    Then: x = (-2±√2)/2

    let α = (-2+√2)/2
    let β = (-2-√2)/2

    log_2(α) + log_2(β)
    = log_2(αβ)
    = log_2((-2+√2)(-2-√2)/4)
    = log_2(1/2)
    = -1

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    posted by Graham

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