Physics

The filament of a 60W lightbulb is at 2.8kK.

What's the surface area of the filament?

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asked by Anonymous
  1. find the energy/area at2800K.
    http://en.wikipedia.org/wiki/Stefan%E2%80%93Boltzmann_law
    but energy=60w
    solve for area

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    posted by bobpursley

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