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find the dimension of a rectangle with a perimeter of 54 cm if its length is 3cm less than twice its width also find the area of the rectangle

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asked by 654
  1. Set up a system of equations:
    Let
    W=width
    L=length
    then
    Perimeter =
    54 = 2(L+W) ...(1)
    L=2W-3 ...(2)

    Solve W by substituting (2) in (1), and hence solve for L.

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    posted by MathMate

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