Styrene is a hydrocarbon. If .438 g of the compound is burned and produces 1.48 g CO2 and .303 g of H2O what is the empirical formula of the compound?
mols C = mols CO2 = 1.48/44 = 0.0346
mols H = 2*mols H2O = 2*0.303/18 = 0.0337
ratio is 1:1. Empirical formula is CH.