Physics

A stone is thrown vertically upward with a speed of 19.0m/s

How fast is it moving when it reaches a height of 10.0m

asked by Lindsay
  1. Ke at bottom = (1/2) m v^2 = 180.5 m

    Pe at top = m g h = m (9.81)(10) = 98.1 m

    Ke lost in rise = 98.1 m
    so
    Ke at top = (1/2)m v^2 = (180.5-98.1) m

    so
    (1/2) v^2 = 82.4
    so
    v = 12.8 m/s

    posted by Damon

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