Physics
A stone is thrown vertically upward with a speed of 19.0m/s
How fast is it moving when it reaches a height of 10.0m
asked by
Lindsay

Ke at bottom = (1/2) m v^2 = 180.5 m
Pe at top = m g h = m (9.81)(10) = 98.1 m
Ke lost in rise = 98.1 m
so
Ke at top = (1/2)m v^2 = (180.598.1) m
so
(1/2) v^2 = 82.4
so
v = 12.8 m/sposted by Damon
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