If 51J of heat is added to an aluminum can with a mass of 23.0g , what is its temperature change? Specific heat capacity of aluminum is 0.903 J/g∘C.
q = 51 = mass x heat cap x delta T.
Solve for delta T.
To find the temperature change of the aluminum can, you can use the formula:
Q = mcΔT
Where:
Q = heat energy (in joules)
m = mass of the aluminum can (in grams)
c = specific heat capacity of aluminum (in J/g∘C)
ΔT = change in temperature (in ∘C)
In this case, you are given the heat energy added, the mass of the aluminum can, and the specific heat capacity of aluminum. Plug in the values into the formula to find the temperature change:
Q = 51J
m = 23.0g
c = 0.903 J/g∘C
ΔT = ?
Rearrange the formula to solve for ΔT:
ΔT = Q / (mc)
Substitute the given values:
ΔT = 51J / (23.0g * 0.903 J/g∘C)
Now, calculate:
ΔT = 2.366 ∘C
Therefore, the temperature change of the aluminum can is approximately 2.366 degrees Celsius.