suppose you are building a fence for a garden in your yard. your yard is 50 ft wide and has an area of 500 square ft.
your father has 88 feet of garden fencing,so your garden has to have a perimeter of 88 ft. how big an area would you set aside for your garden?
2L + 2W = 88
88 factors into 2 * 2 * 2 * 11
Use that info to find your L and W, then multiply L*W = area.
213.2 squared
To determine the area of the garden, we need to first find the dimensions of the garden that satisfy both the width requirement (50 ft) and the perimeter requirement (88 ft). Let's break down the problem step by step:
1. Start by representing the dimensions of the garden:
- Let's assume the width of the garden is x ft.
- Since the yard is square, the length of the garden would also be x ft.
2. Calculate the perimeter of the garden using the given fencing:
- The perimeter of the garden is equal to the sum of all sides.
- In this case, the perimeter is given as 88 ft, so we get the equation: 2x + 2x = 88.
3. Solve the equation to find the dimensions of the garden:
- Simplifying the equation, we get: 4x = 88.
- Dividing both sides by 4, we find: x = 22.
- Hence, the width and length of the garden would both be 22 ft.
4. Calculate the area of the garden:
- The area of a rectangle (or square) is given by multiplying the width by the length.
- Therefore, the area of the garden is: 22 ft * 22 ft = 484 square ft.
Thus, you would need to set aside an area of 484 square ft for your garden.