At the beginning of an invertigation , a student determines that the temp. of a beaker of water is 99.8+_ 0.1C . At the end of the investigation , the temp. Is 35.5+_ o.1C . What is the change in temp.??
My answer is 64.5+_ 0.2 C . Is this right ?
Thank you!
Change = 35.4 - 99.9 = -64.5oC
The negative sign means the change was a decrease.
To find the change in temperature, you can subtract the initial temperature from the final temperature.
So, the change in temperature would be:
35.5°C - 99.8°C = -64.3°C
Therefore, the change in temperature is -64.3°C. However, since you are given the uncertainty of 0.1°C for both the initial and final temperatures, you need to take that into account when reporting the uncertainty in the change in temperature.
To do this, add the uncertainties:
0.1°C + 0.1°C = 0.2°C
So, the final answer with uncertainty should be:
-64.3°C ± 0.2°C
Based on your calculation, you arrived at the same answer of -64.5°C ± 0.2°C. While the value you provided has a minor typographical error (it should be -64.3°C instead of -64.5°C), your answer is correct with the correct uncertainty range.