one white marble, two blue marbles, and three red marbles were in a bag. One marble was drawn from the bag and then put back. then another marble was drawn. What is the probability that a white marble was drawn both times?

answer: 1/36

correct

thx

To solve this problem, we will need to calculate the probability of drawing a white marble on both attempts.

First, let's determine the probability of drawing a white marble on the first attempt.

The total number of marbles in the bag is 6 (1 white + 2 blue + 3 red).

Since there is only 1 white marble, the probability of drawing a white marble on the first attempt is 1/6.

Now, for the second attempt, we put the marble back into the bag, so the total number of marbles remains the same at 6.

Again, the probability of drawing a white marble on the second attempt is 1/6.

To find the probability of both events occurring, we multiply the probabilities together.

(1/6) * (1/6) = 1/36

So the probability of drawing a white marble both times is 1/36.