one white marble, two blue marbles, and three red marbles were in a bag. One marble was drawn from the bag and then put back. then another marble was drawn. What is the probability that a white marble was drawn both times?
answer: 1/36
correct
thx
To solve this problem, we will need to calculate the probability of drawing a white marble on both attempts.
First, let's determine the probability of drawing a white marble on the first attempt.
The total number of marbles in the bag is 6 (1 white + 2 blue + 3 red).
Since there is only 1 white marble, the probability of drawing a white marble on the first attempt is 1/6.
Now, for the second attempt, we put the marble back into the bag, so the total number of marbles remains the same at 6.
Again, the probability of drawing a white marble on the second attempt is 1/6.
To find the probability of both events occurring, we multiply the probabilities together.
(1/6) * (1/6) = 1/36
So the probability of drawing a white marble both times is 1/36.