What is the product of the digits of 7!?

7*6*5*4*3*2*1 = ?

my interpretation:

7! = 5040

the digits of 7! are 5, 0, 4, and 0

their product is 5*0*4*0 = 0

To find the product of the digits of 7!, we first need to calculate the factorial of 7.

To compute the factorial of a number, you multiply that number by all the positive integers less than it, down to 1.

So, to find 7!, you multiply 7 by 6, then by 5, 4, 3, 2, and finally by 1:

7! = 7 × 6 × 5 × 4 × 3 × 2 × 1

Simplifying this multiplication, we get:

7! = 5040

Now that we have the value of 7!, we can find the product of its digits.

To do this, we decompose the number 5040 into its individual digits:

5, 0, 4, and 0.

Next, we multiply these digits together:

5 × 0 × 4 × 0 = 0

Therefore, the product of the digits of 7! is 0.