What is the product of the digits of 7!?
7*6*5*4*3*2*1 = ?
my interpretation:
7! = 5040
the digits of 7! are 5, 0, 4, and 0
their product is 5*0*4*0 = 0
To find the product of the digits of 7!, we first need to calculate the factorial of 7.
To compute the factorial of a number, you multiply that number by all the positive integers less than it, down to 1.
So, to find 7!, you multiply 7 by 6, then by 5, 4, 3, 2, and finally by 1:
7! = 7 × 6 × 5 × 4 × 3 × 2 × 1
Simplifying this multiplication, we get:
7! = 5040
Now that we have the value of 7!, we can find the product of its digits.
To do this, we decompose the number 5040 into its individual digits:
5, 0, 4, and 0.
Next, we multiply these digits together:
5 × 0 × 4 × 0 = 0
Therefore, the product of the digits of 7! is 0.