my ques is 2Fe2S3+3O2+6H2O-4Fe(OH)3+6S THIS REACTION WRIGHT ,WRONG PLZ JUST REPLY I AM WAIT FOR YOUR ANSWER.
The given chemical equation is:
2Fe2S3 + 3O2 + 6H2O → 4Fe(OH)3 + 6S
Based on this equation, it appears to be balanced correctly.
Based on the provided chemical equation, it appears to be unbalanced. The number of atoms for each element on both sides of the equation should be equal. To balance the equation, follow these steps:
Step 1: Count the number of atoms for each element on both sides.
On the left side:
- Iron (Fe): 2 atoms
- Sulfur (S): 6 atoms
- Oxygen (O): 3 atoms
- Hydrogen (H): 12 atoms
On the right side:
- Iron (Fe): 12 atoms
- Oxygen (O): 12 atoms
- Hydrogen (H): 18 atoms
- Sulfur (S): 6 atoms
Step 2: Balance the atoms one at a time.
Start with atoms that appear in only one compound on each side. In this case, it is sulfur (S).
On the left, there are 6 sulfur atoms, while on the right, there are only 6 sulfur atoms. Therefore, sulfur is already balanced.
Next, let's balance oxygen (O). On the left, there are 3 oxygen atoms, while on the right, there are 12 oxygen atoms. To balance it, we need to add 9 more oxygen atoms on the left side.
So the updated equation becomes:
2Fe2S3 + 3O2 + 6H2O → 4Fe(OH)3 + 6S + 9O2
Step 3: Finally, balance hydrogen (H). On the left, there are 12 hydrogen atoms, and on the right, there are 18 hydrogen atoms. To balance it, we need to add 6 more water molecules (H2O) on the left side.
The balanced equation is:
2Fe2S3 + 3O2 + 6H2O → 4Fe(OH)3 + 6S + 9O2
Please note that the reaction you provided might not be chemically accurate, and the balanced equation is the mathematical representation based on the given reactants and products.