if a rock climber accidentally drops a 56 gram piton from a height of 375 meters, what would its speed be before striking the ground ignore the air resistance
To calculate the speed of the piton before it strikes the ground, you can use the equation for the final velocity for an object in free fall. The equation is:
Vf = √(2gh)
Where:
Vf = final velocity (speed)
g = acceleration due to gravity (approximately 9.8 m/s²)
h = height from which the piton is dropped
Using the given information, the height (h) is 375 meters. We can substitute those values into the equation and solve for Vf:
Vf = √(2 * 9.8 m/s² * 375 m)
Vf = √(2 * 9.8 m/s² * 375 m)
Vf = √(7350 m²/s²)
Vf ≈ 85.66 m/s (rounded to two decimal places)
Therefore, the speed of the piton before striking the ground would be approximately 85.66 meters per second.