C7H14O2 + NaOH
What will this combination make? and can it be balanced?
This is probably made easier if you recognize the name of the hydrocarbon: isopentyl acetate
The acetate ion is CH3COO- so we're probably looking for Sodium Acetate as a product. So,
CH3COO-CH2CH2-CH(CH3)2 + NaOH -> CH3COONa + CH2CH2-CH(CH3)2-OH
(I think)
thankyou its meant to be propyl butanoate and sodium hydroxide
The combination of C7H14O2 with NaOH will result in a reaction known as a neutralization reaction. In this reaction, the NaOH (sodium hydroxide) will react with the C7H14O2 (a generic organic compound) to form a salt and water. The balanced chemical equation for this reaction can be represented as:
C7H14O2 + NaOH → NaC7H14O2 + H2O
Now, let's go through the process of balancing this equation.
The number of carbon (C), hydrogen (H), and oxygen (O) atoms on each side of the equation needs to be equal for the equation to be balanced.
On the left side of the equation, there are 7 C atoms, 14 H atoms, and 2 O atoms, while on the right side, there is 1 Na atom, 7 C atoms, 14 H atoms, and 3 O atoms.
To balance the equation, you can start by adjusting the coefficients in front of the compounds. In this case, let's start by balancing the carbon atoms.
By placing a coefficient of 7 in front of NaC7H14O2 on the right side of the equation, the number of carbon atoms becomes equal on both sides.
C7H14O2 + NaOH → 7NaC7H14O2 + H2O
Next, let's balance the hydrogen atoms.
By placing a coefficient of 14 in front of H2O on the right side of the equation, the number of hydrogen atoms becomes equal on both sides.
C7H14O2 + NaOH → 7NaC7H14O2 + 14H2O
Finally, let's balance the oxygen atoms.
By placing a coefficient of 7 in front of NaOH on the left side of the equation, the number of oxygen atoms becomes equal on both sides.
C7H14O2 + 7NaOH → 7NaC7H14O2 + 14H2O
Now, the equation is balanced, and it shows that the combination of C7H14O2 with NaOH will produce 7 molecules of NaC7H14O2 (a salt) and 14 molecules of H2O (water).