A cylindrical ring of thickness 3.5mm.Each ring has internal diameter 14 mm and external diameter 16 mm.Taking pie=3.14 calculate the volume of maetla in single link chain,writing your answer correc to 3 significant figs.
Find the volume of a disk the diameter of the outer ring, and then the volume of a disk of the inner ring diameter, subtract them.
Volumeouter=thickness*PI*radiusouter^2
that should get you started.
I don't see how a ring can be a cylinder. If it is a cylinder bent into a circular ring, then the thickness should equal half the distance between inner and outer diameters, but it doesn't here.
YEs
To calculate the volume of metal in a single link chain, we need to consider the volume of the cylindrical ring.
The volume of a cylinder can be calculated using the formula V = π * r^2 * h, where V represents the volume, π is a mathematical constant (usually approximated as 3.14), r is the radius of the cylinder, and h is the height (or thickness) of the cylinder.
Given that the ring has an internal diameter of 14 mm and an external diameter of 16 mm, we can determine the radius of the cylinder by dividing the diameter by 2:
Internal radius (r1) = 14 mm / 2 = 7 mm
External radius (r2) = 16 mm / 2 = 8 mm
Now, let's calculate the volume of metal in the ring by subtracting the volume of the internal cylinder (hole) from the volume of the external cylinder:
Volume of metal = π * (r2^2 * h) - π * (r1^2 * h)
= π * h * (r2^2 - r1^2)
Given that the thickness of the ring is 3.5 mm, we can substitute h = 3.5 mm and π = 3.14 into the formula:
Volume of metal = 3.14 * 3.5 * (8^2 - 7^2)
= 3.14 * 3.5 * (64 - 49)
= 3.14 * 3.5 * 15
= 164.955 cm^3 (rounded to 3 significant figures)
Therefore, the volume of metal in a single link chain is approximately 165 cm^3 (rounded to 3 significant figures).