What percent of the first 50 positive integers contain no odd digits?

half the ones

half the 20's,40's,60's,80's

Looks like 5+4*5 = 25

28

To find the percentage of the first 50 positive integers that contain no odd digits, we need to count how many of these integers meet that criteria and then express this count as a percentage of the total count (which is 50).

First, let's determine which positive integers contain no odd digits. An integer contains no odd digits if all its digits are even. The even digits are 0, 2, 4, 6, and 8.

To count the number of positive integers with no odd digits, we can analyze the digits one by one.

For the units digit (the rightmost digit), there is a 50% chance (since half of the digits are even) that it will be even (i.e., 0, 2, 4, 6, or 8).

For the tens digit, again, there is a 50% chance that it will be even.

Since these digits are independent of each other, we can multiply the probabilities of each digit being even. Therefore, the proportion of numbers with no odd digits from 1 to 50 is (0.5) * (0.5) = 0.25.

Finally, to get the percentage, we multiply the proportion by 100: 0.25 * 100 = 25%.

Thus, 25% of the first 50 positive integers contain no odd digits.