Automobile batteries contain sulfuric acid, which is commonly referred to as "battery acid." Calculate the number of grams of sulfuric acid in 0.650 L of battery acid if the solution has a density of 1.28 g/mL and is 38.1% sulfuric acid by mass.
density = 1.28 g/mL.
mass of 0.650L = 1.28 g/mL x 650 mL = ?
mass of H2SO4 in that volume = ? x 0.381 = xx.
Post your work if you get stuck.
309.5625
mass of H2SO4 IN VOLUME=1.28*0,381=0,43
To calculate the number of grams of sulfuric acid in 0.650 L of battery acid, you need to consider the density and the mass percent concentration of sulfuric acid.
Step 1: Calculate the mass of the battery acid.
Mass = density x volume
Given:
Density = 1.28 g/mL
Volume = 0.650 L
Convert volume from liters to milliliters:
0.650 L x 1000 mL/L = 650 mL
Mass = 1.28 g/mL x 650 mL = 832 g
Step 2: Calculate the mass of sulfuric acid in the battery acid.
Mass_sulfuric_acid = Mass_battery_acid x mass_percent_sulfuric_acid
Given:
Mass_battery_acid = 832 g
Mass_percent_sulfuric_acid = 38.1%
Mass_sulfuric_acid = 832 g x 0.381 = 317.19 g
Therefore, there are approximately 317.19 grams of sulfuric acid in 0.650 L of battery acid.