Rounding to the nearest thousands make me 8000.and the sum of my digit is 24. what number can i be?

7845?

To find the number that rounds to the nearest thousands and has a sum of digits equal to 24, we will need to do some calculations. Let's break it down step by step:

Step 1: Rounding to the nearest thousands means that the digits after the thousands place should be 0. Given that the number rounds to 8000, we know that it could be any number between 7500 to 8499 since rounding down would be 8000 and rounding up would be 8500.

Step 2: Let's focus on the sum of the digits being equal to 24. This means that when we add up all the digits in the number, the result should be 24. To find the number, we can use trial and error approach.

Let's start with the highest possible digit in the thousands place, which is 8. We then have 3 digits remaining to add up to 24.

Since the sum of digits is 24, the hundreds, tens, and units place digits must add up to 24-8=16.

Now, we have several possibilities for three digits adding up to 16. Keep in mind that the digits can range from 0 to 9.

Let's use trial and error to find the combination that gives the sum of 16:

- 9 + 6 + 1 = 16
- 8 + 7 + 1 = 16
- 8 + 6 + 2 = 16
- 7 + 7 + 2 = 16
- 7 + 6 + 3 = 16
- 6 + 6 + 4 = 16

Out of these possibilities, we need to find the one where the digits are in a valid range for our problem. Since the number should be rounded to the nearest thousands, we must choose lower numbers for the remaining digits.

The combination that satisfies this condition is 7862. Therefore, the number that rounds to the nearest thousands and has a sum of digits equal to 24 is 7862.

Please note that the above solution is one of many possible answers, and there might be other combinations that give the same result.