A body of mass 17.25kg rest on a smooth horizontal table. The coefficient of friction between the body and the table is 0.34. What is the horizontal frictional force that will make the body just slide.
Wb = m*g = 17.25kg * 9.8N/kg = 169 N. = Wt of body.
Fv = m*g = 169 N. = Force perpendicular to the table.
Fs = u*Fv = 0.34*169 = 57.5 N. = Force of static friction.
To find the horizontal frictional force that will make the body just slide, we need to consider the maximum static friction. When the body is at rest, the static frictional force is equal to the force applied on the body in the opposite direction.
The maximum static frictional force (Fstatic_max) can be calculated using the equation:
Fstatic_max = μ * N,
where μ is the coefficient of friction and N is the normal force exerted on the body.
The normal force (N) exerted on the body is equal to its weight (mg), where m is the mass of the body and g is the acceleration due to gravity (approximately 9.8 m/s^2).
N = mg.
Substituting the given values, we have:
m = 17.25 kg
g = 9.8 m/s^2
μ = 0.34
N = (17.25 kg) * (9.8 m/s^2).
Now we can calculate the maximum static frictional force:
Fstatic_max = (0.34) * [(17.25 kg) * (9.8 m/s^2)].
Calculating this expression will give you the value of the maximum static frictional force, which is the same as the horizontal frictional force required to make the body just slide.