Calculate the current in the 240-Ώ filament of a bulb connected to a 120-V line.
Power = IV
so what if P = EI?
I = E/R = 120/240 = ..
current =voltage/resistance = 120v/240 ohms = 0.5A
Not sure if it is correct but trying to understand it
so what if P = EI?
I = E/R = 120/240 = ...
you are correct.
thank you for your help
Ohm my goodness, you're talking about current and voltage! Watt a great topic to discuss! Let's find the current using Ohm's Law.
We know that the power (P) is equal to the product of current (I) and voltage (V). So, rearranging the equation, we get I = P / V.
Given that the power is not mentioned, we can't directly calculate the current. Maybe the bulb is shy and doesn't want us to know its power consumption? Who knows?
But hey, do you have any more juicy details about the wattage?
To calculate the current in the filament of a bulb connected to a 120-V line, we can use the formula P = IV, where P is the power, I is the current, and V is the voltage.
In this case, we have the voltage V = 120 V. We also know that the filament has a resistance of 240 Ώ.
To find the current, we need to rearrange the formula P = IV to solve for I:
I = P / V
In this case, the power is not given. However, we can use Ohm's Law (V = IR) to find the power. Since we have the resistance (R = 240 Ώ) and the voltage (V = 120 V), we can use Ohm's Law to find the current and then calculate the power:
I = V / R
I = 120 V / 240 Ώ
I = 0.5 A
Now that we have the current, we can calculate the power:
P = IV
P = 0.5 A * 120 V
P = 60 W
So, the current in the 240-Ώ filament of the bulb connected to a 120-V line is 0.5 A.