A 500kV power line has a maximum Voltage drop of 3% and is design to carry 1000 Amps. If the conductor has a 0.026 ohms/km resistance, what is the maximum distance the conductor can be run (to the nearest complete km)? Hint: P=IE, E=IR
How do you solve this?
Please help and thank you
Rmax = V/I = (500000*.97)/1000=485 Ohms=Max. conductor resistance.
Dmax = 485 Ohms / 0.026Ohms/km=18,654 km.