a horizontal force of 124 N is used to pull a 1026 N load.What is the coefficient of friction?
Fap-Ff = m*a
124-Ff = m*0 = 0
Ff = 124 N. = Force of friction.
u = Ff/Fl = 124/1026 = 0.121 = Coefficient of friction.
Fap = Force applied.
124-Ff = m*0 = 0
Ff = 124 N. = Force of friction.
u = Ff/Fl = 124/1026 = 0.121 = Coefficient of friction.
Fap = Force applied.