Can someone help me on how to do this problem

2xy(3x^2)(4y^-1)(5z^-3)

What is the power of y? Is it 2? Are you supposed to multiply it all out?

It is not clear what the "problem" is. You cannot solve for x, y and z with one equation. In fact, you have not even written an equation.

You have already done a lot of factoring, but 4y^2 -1 and 5z^3 -3 can be factored some more.

well it says to simplify.and that's all it gives me.

its either one of the following answers
a.6x^3/20z^3
b.6x^3y^2/20z^2
c.120x^3/z^3
d.120x^3z^3

its (c), 120x^3/z^3.

thank you.

how did you get the answer?

Of course! I'd be happy to help you with this problem.

To simplify the expression 2xy(3x^2)(4y^-1)(5z^-3) and find the final answer, we'll follow some basic rules of exponents and multiplication.

First, let's break down the expression and simplify each term:
2xy * 3x^2 * 4y^-1 * 5z^-3

We'll start by multiplying the coefficients together: 2 * 3 * 4 * 5 = 120

Next, we need to simplify each variable term separately.

For the x terms:
x * x^2 = x^(1+2) = x^3

For the y terms:
y * y^-1 = y^(1 + -1) = y^0 = 1 (since any number raised to the power of 0 is equal to 1)

Finally, for the z terms:
Since there is no z term given in the expression, we'll keep it as it is: z^-3

Now, let's put it all together:
2xy * 3x^2 * 4y^-1 * 5z^-3 = 120x^3 * 1 * z^-3

Simplifying further, we can remove the y term since it equals 1:
120x^3 * 1 * z^-3 = 120x^3 * z^-3

And that's the simplified form of the expression!