a 200 newtoon wagon is to be pulled up a a 30 degrees incline at constant speed. how large a force parallel to the incline is needed if friction are negligible?
F=mgsinα=Wsinα =200 x 0.5 =100 N
To determine the force required to pull the wagon up the inclined plane, we need to analyze the forces acting on the wagon.
Let's break down the forces involved:
1. Gravitational Force (Weight):
The weight of the wagon is given as 200 newtons. Since we are pulling the wagon up the incline, we need to find the component of this weight acting parallel to the incline.
The weight acting along the incline can be found using the formula:
Weight parallel to incline = Weight × sin(θ)
where θ is the angle of the incline (30 degrees).
Weight parallel to incline = 200 N × sin(30°)
Weight parallel to incline = 200 N × 0.5
Weight parallel to incline = 100 N
2. Parallel Force:
The force parallel to the incline is the force needed to counteract the weight acting along the incline. This force has the same magnitude as the weight parallel to the incline but acts in the opposite direction.
Therefore, the force parallel to the incline required to pull the wagon up at a constant speed is 100 newtons.