Calculate the molarity of 1 lit solution of 93% H2SO4 by weight by volume even the density of solution is 1.84 g/ml
To calculate the molarity of a solution, you need to know the concentration of the solute in moles and the volume of the solution in liters. In this case, we have a concentrated sulfuric acid solution, and we need to calculate the molarity.
Step 1: Determine the mass of the solute (H2SO4)
Since we have a solution of 93% H2SO4 by weight, it means that 100 mL of the solution contains 93 g of H2SO4.
To calculate the mass of H2SO4 in 1 L of the solution, we can use the density of the solution.
Mass of 1 L of solution = density × volume
Mass of 1 L of solution = 1.84 g/mL × 1000 mL
Mass of 1 L of solution = 1840 g
Therefore, 1 L of the solution contains 1840 g of the solution.
To determine the mass of H2SO4 in 1 L of the solution, we multiply the mass of the solution by the concentration of H2SO4:
Mass of H2SO4 = 1840 g × (93/100)
Mass of H2SO4 = 1709.2 g
Step 2: Convert grams of H2SO4 to moles of H2SO4
To convert grams to moles, we need to know the molar mass of H2SO4 (98.08 g/mol).
Moles of H2SO4 = Mass of H2SO4 / Molar mass of H2SO4
Moles of H2SO4 = 1709.2 g / 98.08 g/mol
Moles of H2SO4 ≈ 17.44 mol
Step 3: Calculate molarity
Now that we know the moles of H2SO4 and the volume of the solution, we can calculate the molarity.
Molarity (M) = Moles of solute / Volume of solution in liters
Molarity (M) = 17.44 mol / 1 L
Molarity (M) ≈ 17.44 M
Therefore, the molarity of the 1 L solution of 93% H2SO4 is approximately 17.44 M.
17.5
mass of 1L of the solution is
grams = 1.84 g/mL x 1000 mL = 1840g
mass H2SO4 in that 1840 g is
1840 x 0.93 = ?
mols H2SO4 = ?g H2SO4/molar mass H2SO4.
M H2SO4 = mols/L