A trolley while going down an inclined plane has an acceleration of 2 cm/s2.What will be the velocity 3 secs after its start?
v = at
you have a and t, so plug them in.
v=at
V=0.2*3
v=0.6
v=at
v=0.02*3v=0.06
To find the velocity of the trolley 3 seconds after its start, we can use the equation of motion for uniformly accelerated motion:
v = u + at
Where:
v = final velocity
u = initial velocity (which is usually assumed to be 0 for objects starting from rest)
a = acceleration
t = time
In this case, the acceleration (a) is given as 2 cm/s², and the time (t) is given as 3 seconds. We can substitute these values into the equation and solve for v.
v = 0 + (2 cm/s²) * (3 s)
v = 0 + 6 cm/s
v = 6 cm/s
Therefore, the velocity of the trolley 3 seconds after its start is 6 cm/s.