This balance equation shows the burning of octane in air. 2C8H18 + 25O2 ----> 16CO2 + 18H2O. How many grams of carbondioxide will be produced when 1 mole of octane burns completely?
You have the equation.
Convert 1 mol octane to mols CO2. That will be 1 mol C8H18 x (16 mols CO2/2 mol C8H1*) = 1 x (16/2) = 8.
Then g CO2 = mols CO2 x molar mass CO2.
To determine the number of grams of carbon dioxide produced when 1 mole of octane (C8H18) burns completely, we need to use the stoichiometric coefficients from the balanced equation.
The balanced equation tells us that 2 moles of octane react with 25 moles of oxygen to produce 16 moles of carbon dioxide.
Given that the molar mass of carbon dioxide is approximately 44 grams/mol, we can now calculate the mass of carbon dioxide produced when 1 mole of octane burns completely.
Number of moles of carbon dioxide produced = (16 moles CO2 / 2 moles C8H18) * 1 mole C8H18 = 8 moles CO2
Mass of carbon dioxide produced = Number of moles of carbon dioxide * molar mass of carbon dioxide
= 8 moles CO2 * 44 grams/mol = 352 grams
Therefore, when 1 mole of octane (C8H18) burns completely, it will produce 352 grams of carbon dioxide.