Window cleaner contains ammonium hydroxide. A 10.00 mL sample of window cleaner is titrated with 38.5 mL of 0.311 M hydrochloric acid. what is the molarity of the ammonium hydroxide in the window cleaner?
Well, it seems like you've got a cleaning conundrum on your hands! Let me help you out.
We can start by using the equation:
Molarity × Volume = Molarity × Volume
Since the ammonium hydroxide and hydrochloric acid react in a 1:1 ratio, we can say:
Molarity of ammonium hydroxide × Volume of ammonium hydroxide = Molarity of hydrochloric acid × Volume of hydrochloric acid
Plugging in the values:
Molarity of ammonium hydroxide × 10.00 mL = 0.311 M × 38.5 mL
Solving for the molarity of ammonium hydroxide:
Molarity of ammonium hydroxide = (0.311 M × 38.5 mL) / 10.00 mL
Calculating that, we get:
Molarity of ammonium hydroxide = 1.203 M
So, the molarity of the ammonium hydroxide in the window cleaner is approximately 1.203 M. Now, please don't go titrating all your cleaning supplies!
To determine the molarity of the ammonium hydroxide in the window cleaner, we can use the concept of stoichiometry and the balanced chemical equation between ammonium hydroxide (NH4OH) and hydrochloric acid (HCl):
NH4OH + HCl → NH4Cl + H2O
From the balanced equation, we can see that the ratio of NH4OH to HCl is 1:1. This means that 1 mole of HCl reacts with 1 mole of NH4OH.
First, let's calculate the number of moles of HCl used in the titration:
Moles of HCl = Concentration of HCl * Volume of HCl in liters
= 0.311 M * (38.5 mL / 1000 mL/L)
= 0.0119635 moles
Since the ratio of NH4OH to HCl is 1:1, the number of moles of NH4OH present in the window cleaner is also 0.0119635 moles.
Next, we need to determine the volume of the window cleaner sample in liters. Since the sample is given in milliliters, we will convert it:
Volume of window cleaner sample = 10.00 mL * (1 L / 1000 mL)
= 0.010 L
Finally, we can calculate the molarity of ammonium hydroxide in the window cleaner:
Molarity of NH4OH = Moles of NH4OH / Volume of NH4OH in liters
= 0.0119635 moles / 0.010 L
= 1.19635 M
Therefore, the molarity of the ammonium hydroxide in the window cleaner is approximately 1.196 M.
To find the molarity of ammonium hydroxide in the window cleaner, we can use the concept of stoichiometry and the balanced chemical equation of the reaction between ammonium hydroxide (NH4OH) and hydrochloric acid (HCl):
NH4OH + HCl → NH4Cl + H2O
From the balanced equation, we can see that one mole of ammonium hydroxide reacts with one mole of hydrochloric acid to produce one mole of ammonium chloride and one mole of water.
First, let's determine the number of moles of hydrochloric acid used in the titration:
moles of HCl = molarity of HCl × volume of HCl used
= 0.311 M × 38.5 mL
= 11.9235 mmol (millimoles)
Since the stoichiometry of the reaction tells us that the molar ratio of HCl to NH4OH is 1:1, we can conclude that the number of moles of ammonium hydroxide present in the window cleaner is also 11.9235 mmol.
Now, we can determine the molarity of the ammonium hydroxide:
molarity of NH4OH = moles of NH4OH / volume of NH4OH
= 11.9235 mmol / 10.00 mL
= 1.19235 M
Therefore, the molarity of the ammonium hydroxide in the window cleaner is approximately 1.19235 M.
NH4OH + HCl ==> NH4Cl + H2O
mols HCl = M x L = ?
mols NH4OH = same (look at the coefficients in the balanced equation; i.e., 1 mol HCl = 1 mol NH4OH).
M NH4OH = mols NH4OH/L NH4OH = ?
I should note here that it has been shown that NH4OH doesn't exist; i.e, that aqueous NH3 is just that, NH3(aq). In solution it forms NH4^+ and OH^- so the chemistry of aq NH3 is not changed.