# math correction

can someone correct this for me.

Business and finance. The cost for a long-distance telephone call is \$0.36 for the first minute and \$0.21 for each additional minute or portion thereof. Write an inequality representing the number of minutes a person could talk without exceeding \$3.
Let x = be the number of minutes:
The first minute cost \$0.36
The remaining x –1 minutes cost \$0.21 each
So the remaining x- 1 minutes altogether costs \$0.21 (x – 1)

Total cost = \$0.36 + \$0.21 (x – 1)

This must be less than or equal \$3.00. So we have:
\$0.36 +\$0.21 (x- 1) <= \$ 3.00
Multiply through by 100 and drop the \$’s
36 + 21(x –1)<= 300
12 + 7 (x –1)<= 100 (In this step in order to get this equation I had to divide both sides by 3 to make the numbers smaller.)
12 + 7x – 7 <= 100
7x + 5 <=100

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